longest-substring-without-repeating-characters

you are given a string ‘s’ ,and return the max length and no repeat character substring of it

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func lengthOfLongestSubstring(s string) int {
helpMap := make(map[rune]int)
firstPoint := 0
secondPoint := 0
runes := []rune(s)
maxLength := 0
for firstPoint < len(runes) {
firstRune := runes[firstPoint]
value, ok := helpMap[firstRune]
if ok {
helpMap[firstRune] = value + 1
if helpMap[firstRune] > 1 {
if firstPoint-secondPoint > maxLength {
maxLength = firstPoint - secondPoint
}
for secondPoint <= firstPoint {
secondRune := runes[secondPoint]
_, ok := helpMap[secondRune]
if ok {
helpMap[secondRune] = helpMap[secondRune] - 1
}
secondPoint = secondPoint + 1
if helpMap[firstRune] <= 1 {
break
}
}
}
} else {
helpMap[firstRune] = 1
}
firstPoint = firstPoint + 1
}
if firstPoint-secondPoint > maxLength {
maxLength = firstPoint - secondPoint
}
return maxLength
}

longest-substring-without-repeating-characters
http://orikey0.github.io/2024/02/09/longest-substring-without-repeating-characters/
作者
Howard Lee
发布于
2024年2月9日
许可协议